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the correct equation is either ( 1 + 1 - x ) 2 - 6 ( 1 + 1 + x)= - 8

or

( 1 + 1 + x ) 2 - 6 ( 1 + 1 + x ) = - 8

and for both the equation solution is x=0

substitute x=0 in LHS

=> ( 1 + 1 - 0) 2 - 6 ( 1 + 1 + 0 )

=> 4-6(2)

=>4-12

=>-8

hence

LHS= RHS

=>(1 + 1 + 0) 2 - 6 ( 1 + 1 + 0)

=>4-12

=>-8

hence

LHS=RHS"

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