"Solution:Given ( 1 + 1 = x ) 2 - 6 ( 1 + 1 + x ) = - 8
the correct equation is either ( 1 + 1 - x ) 2 - 6 ( 1 + 1 + x)= - 8
or
( 1 + 1 + x ) 2 - 6 ( 1 + 1 + x ) = - 8
and for both the equation solution is x=0
substitute x=0 in LHS
=> ( 1 + 1 - 0) 2 - 6 ( 1 + 1 + 0 )
=> 4-6(2)
=>4-12
=>-8
hence
LHS= RHS
=>(1 + 1 + 0) 2 - 6 ( 1 + 1 + 0)
=>4-12
=>-8
hence
LHS=RHS"
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