EXPAND USING BINOMIAL THOREM(2X+3)^5 I am not sure what you are looking for, but I believe you need to recognize that the power is 5 and the two terms needed are 2x and 3. To expand take the first term and put it to power 5 and the second term to power 1. The steps are to decrease the first termand increase the second term. (2x)^5 + 3 + (2x)^4 + 3^2 + (2x)^3 + 3^3 + (2x)^2 + 3^4 + 2x + 3^5 = 32x^5 + 3 + 16x^4 + 9 + 8x^3 + 27 + 4x^2 + 64 + 2x + 192 = 32x^5 + 16x^4 + 8x^3 + 4x^2 + 2x + (3 + 9 + 27 + 64 + 192 = 32x^5 + 16x^4 + 8x^3 + 4x^2 + 2x + 295