2x^2 = 2x - 5
2x^2 - 2x + 5 = 0
use quadratic equation to solve:
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x = [-b ± √b2 - 4 a c ] / 2a
substitute into the equation:
a = 2, b = -2, c = -5
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x = [-(-2) ± √(-2)2 - 4*2*(-5) ]
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2*2
_______ __ __
x = [2 ± √(4 + 40 ] 2 ± √44 2(1 ± √11)
------------------- = ------------ = --------------
4 4 4
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x = 1 ± √11
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2