Both boats go 32 miles. One with the current. One against the current. The rate of the current for both boats was 4mph. It took the boat going against the current 2 hours longer than the other boat, who's time is unknown. Find the rate of the boat in calm water.
I had set it up like this 32/4+B = 32/4-B + 2
In other terms D / R+B = T so... D / R+B = D / R-B + 2
please solve by either factoring, square root, completing the sqare or quadratic formula