Question: Find Parametric equations for the line segment joining the points (6 , 7 ) and ( 10 , 10 ).
The equation of the line joining these two points is:
(y - y1)/(x - x1) = (y2 - y1)/(x2 - x1)
(y - 7)/(x - 6) = (10 - 7)/(x - 6) = 3/4
cross-multiplying,
4(y - 7) = 3(x - 6)
Equality is maintained in the above equation by letting
(y - 7) = 3t and (x - 6) = 4t ( 4*3t == 3*4t )
Hence y = 7 + 3t and x = 6 + 4t, 0<t<1 i.e. Option D