Solve this.. ◻➕◻➕◻➕◻➕◻=30 Fill the boxes using (1, 3, 5, 7, 9, 11, 13, 15) U can also repeat the numbers..
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Solve this.. ◻➕◻➕◻➕◻➕◻=30 Fill the boxes using (1, 3, 5, 7, 9, 11, 13, 15)

3 + 7 + 9  + 11  = 30

Do there have to be 5 numbers?  I solved with only 4 numbers.

13 + 5 + 5 + 7 = 30

15 + 5 + 3 + 1 + 5 + 1 = 30
by Level 10 User (55.7k points)
3! + 3! + 3! + 3! + 3! = 30
by
19+5+3+1.5+1.5
by
11+7+5+1+3!=30

3!=3*2*1=6 (factorial of 3

so 11+7+5+1+6=30
by

(11-1)+(5-1)+(9-1)+(5-1)+(9-5)=30

by
(7-1)+(15-9)+(11-5)+(13-3)+(3-1)=30
by
13+11+3+3+3=30
But the base is 13, it is not a requirement to use the decimal system.
by

All the given numbers are odd. The sum of any set of odd numbers is always odd if the quantity of the numbers in the sum is also odd.

All odd numbers can be expressed as 2n+1 where n is any number. For example, 1=2×0+1, 7=2×3+1, etc. In this example, the first n=0 and the second n=3.

If we have 5 odd numbers: 2n1+1, 2n2+1, 2n3​​​​​​​+1, 2n4​​​​​​​+1, 2n5​​​​​​​+1, then add them together we get:

2(n1+n2+n3+n4+n5)+5 which can be written 2(n1+n2+n3+n4+n5+2)+1. We can represent the sum in parentheses by a single number N, so the sum is 2N+1 which is always an odd number. Therefore the sum can never be 30, which is even.

by Top Rated User (1.2m points)

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