f(x)=4-2ln(x+1)
y = 4 - 2ln( x + 1 ) ⇒ x + 1 > 0 ⇒ x > - 1
D: ( - 1, + infinitive )
R: all real numbers ( - infinitive, + infinitive )
vertical assymptote x = -1
inverse function
x = 4 - 2ln( y + 1)
2ln( y + 1) = 4 - x
ln( y + 1 ) = ( 4 - x )/2
e^((4 - x)/2) = y + 1
y = e^((4 - x)/2) - 1
D: ( - infinitive, + infinitive )
R: ( - 1, + infinitive)
horisontal asymptote y = - 1