addition for logarithms is equivalent to multiplication so...
log6(x+5)(x) = 2, then using the definition of logarithms, change it to 6^2 = (x+5)(x) and solve
36= x^2 + 5x....0=x^2 +5x - 36
this is factorable to 0=(x+9)(x-4) set each equal to zero and x=(-9) and x=(4), but you cannot take the logarithm of a negative so the only solution is x=4