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finding the length and width of rectangle with perimeter given

The perimeter of a rectangular swimming pool is 50 ft.  If the length is one ft. more than twice the width, find the length and width
asked Feb 19, 2011 in Algebra 1 Answers by anonymous




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23 Answers

if P= perimeter and L = length and W = width then we can write the equation for this problem as follows:

 

L=2W+1

P=50

50= 2W + 1 + 2W+1 + W + W

50=6W + 2

-2   -2

48 = 6W

W = 8

L= 2 X 8 + 1

L= 17

answered Feb 19, 2011 by mshelton Level 4 User (9,310 points)
how do i solve this problem

What is the freeking answer:.....what is the formula for a rectangle?????

answered Jan 19, 2012 by anonymous
That is rude of ya dude.
Perimeter is just twice of length added to twice of breadth.
Area is just length times breadth (not that you will use it here).
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