Find four consecutive even integers so that the sum of the first three is 2 more than twice the fourth.
the four consecutive even integers would be:
x, x+2, x+4,and x+6
Now, sum of the first three is 2 more than twice the fourth.
(x)+(x+2)+(x+4) -2 = 2(x+6)
3x +4 = 2x +12
3x -2x = 12 - 4
x = 8
the four consecutive even integers would be:
8, 10, 12, and 14
check
sum of the first three is 2 more than twice the fourth.
8+10+12 -2 = 2*14
28 = 28