(2 + 3i) (-3-7i)
asked Feb 4, 2012 in Pre-Algebra Answers by anonymous

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1 Answer

(2 + 3i) (-3-7i) =

- 2*3 - 2*7i -3*3i -3*7i^2 =               i^2 = - 1

- 6 - 14i - 9i - 21( - 1) =

-6 - 23i  + 21 =

15 - 23i

answered Feb 4, 2012 by jkhenry Level 8 User (35,840 points)

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