13.5% annually is 13.5/4=3.375% quarterly, so r is 0.03375. The compounding factor is 1.03375, (1+r). The period, T, is 10 years or 40 quarters. The principal is 140000, P.
If the quarterly withdrawal=Q, then after three months P, P grows to P(1+r) and Q is taken out leaving P(1+r)-Q. After 6 months, The amount grows to (P(1+r)-Q)(1+r) and Q is taken out, leaving P(1+r)^2-Q(1+r)-Q. After 9 months the amount after withdrawal is P(1+r)^3-Q(1+r)^2-Q(1+r)-Q, and after 4T periods, the end of the investment period, the amount after withdrawal is zero:
P(1+r)^(4T)-Q(1+r)^(4T-1)-Q(1+r)^(4T-2)-...-Q(1+r)-Q=0.
So P(1+r)^(4T)-Q(1+r)^(4T-1)+...+1)=0, and Q=P(1+r)^(4T)/S, where S is the sum of the series.
(1+r)S-S=((1+r)^(4T)-1) and S=((1+r)^(4T)-1)/r=(1.03375^40-1)/0.03375=82.146.
Q=140000*3.7724275/82.146=6429.28 (answer 3).