x = (-b+/-sqrt(b^2-4ac)) / 2a
x = (4 + sqrt (4^2 - 4*3*3) / (2*3) or x = (4 - sqrt (4^2 - 4*3*3) / (2*3)
in this case the discriminate is negative, so there are two non-real, complex roots, or complex conjugets. However, the question does not ask you to solve anything, so this may be irrelevant.
a=3, b=-4, and c = 3