In triangle ABC <A=75°,<B=34°,the length of a,of the side opposite angle A is 10.2cm .Find the length b,of the side opposite angle B
All we need to do here is use the sine rule. Which is ...
a/sin(A) = b/sin(B)
We have: a = 10.2 cm, A = 75, b = ?, B = 34.
Therefore, 10.2/sin(75) = b/sin(34)
b = 10.2*(sin(34)/sin(75)) = 10.2*(0.55919/0.96592) = 10.2*0.57892
b = 5.90497
Answer: b = 5.9 cm