2^2x+3 =5.2^x+1
asked Feb 9, 2016 in Other Math Topics by Jabulani

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2 Answers

I interpret this as 2^(2x+3)=5*2^(x+1).

Take logs of each side: (2x+3)log2=log5 + (x+1)log2.

2xlog2+3log2=log5+xlog2+log2.

xlog2=log(5*2/8)=log1.25; x=log1.25/log2=0.32193 approx.

CHECK: Put this value into the original equation: 2^(2x+3)=12.5; 2^(x+1)=2.5 so 5*2.5=12.5. The equation balances.

answered Feb 11, 2016 by Rod Top Rated User (417,500 points)

Given 2^(2x+3) =5.2^(x+1)
5.2^(x+1)=(26/5)^(x+1)
2^(2x+3)=(26/5)^(x+1)
4^x=0.65*5.2^x
x=1.64193

answered Feb 16, 2016 by John Marsh Level 8 User (30,400 points)

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