its from sample papers

asked Jul 8, 2016 in Trigonometry Answers by Srijan

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Consider right-angled triangle ABC where B=90 degrees. If A=37 then C=53. BC=x and AB=1, AC=√(1+x^2). sin37=x/√(1+x^2), cos37=1/√(1+x^2).

cosec53=1/sin53=1/cos37=√(1+x^2), so cosec^2(53)=1+x^2.

answered Jul 8, 2016 by Rod Top Rated User (416,100 points)
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