f(n)=3n-4 so f(0)=-4, f(1)=-1, f(2)=2, f(3)=5. (f(4)=8, etc., so it's clear that f(n)=f(n-1)+3.)
In C, D f(0)=-4 and in A, B f(1)=-1. So they are consistent.
In A, f(2)=f(1)+3=-1+3=2 the same as f(2) originally and f(3)=f(2)+3=2+3=5 the same as f(3) originally.
The other options (B and C) are not consistent with the original f(n). So the answer is A. D appears to be the same as A because f(0)=-4 and f(1)=-1 for both A and D.