a³-b³=513 , ab=54 ,a-b=?
asked Nov 20, 2016 in Algebra 1 Answers by Moon

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2 Answers

answered Nov 20, 2016 by Mathical Level 10 User (55,240 points)

Synthetic division by root b gives:

b | 1  0   0    -b^3

     1  b b^2   b^3

     1  b b^2 | 0    = a^2+ab+b^2

So a^3-b^3=(a-b)(a^2+ab+b^2)=513

But ab=54 so (a-b)(a^2+54+b^2)=513

(a-b)^2=a^2-2ab+b^2=a^2+b^2-108 so a^2+b^2=(a-b)^2+108.

Let x=a-b, then a^2+b^2=x^2+108 and x(x^2+108+54)=513,

x(x^2+162)=513, x^3+162x-513=0=(x-3)(x^2+3x+171) (use synthetic division to get this)

There is only one real root, x=3 so a-b=3.

The factors of 54 include 9*6. These numbers differ by 3 (a-b=3=9-6) and 9^3-6^3=729-216=513, making a=9 and b=6.

 

answered Nov 20, 2016 by Rod Top Rated User (416,100 points)
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