differentiation,y=5 tan°x
asked Dec 11, 2016 in Trigonometry Answers by waqas khan

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2 Answers

I read this as "Differentiate y=5tan^2(x) with respect to x."

If p=tan(x) then dp/dx=sec^2(x) and y=5p^2, dy/dp=10p.

dy/dx=dy/dp * dp/dx=10p*sec^2(x)=10tan(x)sec^2(x) by the chain rule.

This can also be written: 10tan(x)(1+tan^2(x)).

answered Dec 11, 2016 by Rod Top Rated User (416,100 points)
y = 5tan^2x

dy/dx = 5*2 tanx*d/dxtanx) =

10 tanx*sec^2(x)

 

the derivate of tanx is sec^2x
answered Dec 11, 2016 by jkhenry Level 8 User (36,160 points)

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