let x be no. of motorbikes and y be no. of cars. We know that cars have 4 tyres each and motorbikes each has 2 tyres. we form simultaneous equations as follows; x+y=94......(1) 2x+4y=310......(2) solving them simultaneously we have, x=94-y substituting this in eqn 2; 2(94-y)+4y=310 =>188-2y+4y=310; 2y=122; y=61 x=94-61; x=33 Thus we have 33 motorbikes and 61 cars. Hint: vehicles(cars + motorbikes)