For parallel lines, they have equivalent gradients; thus we rewrite equation above in the form y=mx+c; where m is the gradient and c is y-intercept. => y=-3/2x+4; we have point(4,1) and we introduce another point say (x,y) on the second line. equation of line two will be (y-1)/(x-4)=-3/2; 2y-2=-3x+12 collect like terms together, 2y=–3x+14, thus answer is 2y=–3x+14