find equation of the line that passes through (2,7) and is parallel to f(x)=2/3x-1
The equation of the straight line is: y = mx + c, where m is the gradient.
Since our straight line is parallel to y = (2/3)x - 1, then it has the same gradient.
i.e. m = 2/3
Since our straight line passes through the point (x,y) = (2, 7), then these coordinate values will satisfy our line equation y = (2/3)x + c.
Subistituting for (x, y) = (2, 7) in our equation,
7 = (2/3)*2 + c
7 = 4/3 + c
c = 7 - 4/3 = 17/3 = 5 2/3
Our straight line is : y = (2/3)x + 5 2/3