What are the coordinates of the vertex of V(w)=−0.25(w−1)^(2)+0.25?
Enter your answer as an ordered pair, using decimal numbers rounded to the hundredths place
What you have here is a quadratic.
The vertex will occur when the slope of the curve is equal to zero.
dV/dw = -0.25*2*(w - 1) = (1 - w )/2
when dV/dw = 0, then w = 1.
At w = 1, V(0) = -0.25*0 + 0.25
V = 0.25
Thus the vertex is at (w, X) = (1, 0.25)