find the derivative of y in;

y=3x^5-5x^3+2/x^2

y=(sinx+2cosx) (1/x+x^2)

y=e^x-e^-x /2x+1

y=3sin (5x^3 -1)

y=3x^5-5x^3+2/x^2

y=(sinx+2cosx) (1/x+x^2)

y=e^x-e^-x /2x+1

y=3sin (5x^3 -1)

y=3x^5-5x^3+2/x^2

y=(sinx+2cosx) (1/x+x^2)

y=e^x-e^-x /2x+1

y=3sin (5x^3 -1)

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