((x^2-1)/sqrt(2x-1) )
Integrating by parts - let u= x^2-1 so u' = 2x, let v' = (2x-1)^-0.5 so v= 2(2x-1)^0.5
(int by parts formula)
Integrating by parts again - u=2x, u'=2 v'= 2(2x-1)^0.5, so v=2/3 (2x-1)^1.5
Feel free to tidy this one up, but the hard part is done :P Also, if i have done any part wrong, please message me as i kept confusing myself with the latex code which is designed to make it easier!