Radius is half the diameter, that is, 10/2=5in. Volume=4π(53)/3=(4×125)π/3=500π/3in3. (Volume of sphere=(4/3)πr3 where r is its radius.)
Density of the clay=1.1oz/in3, so the weight of the statue=1.1×500π/3=550π/3=575.96in3. (density=weight/volume, so weight=density×volume)
To the nearest tenth this is 576.0in3.
(π (pi) has a value of about 3.1416 and is the constant ratio of the diameter and the circumference of a circle)