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Solve for theta , where 0 < theta < 2 pie : (cos theta )(sin 2 theta ) - 2 sin theta + 2 = 0 .

I dont understand how to do this problem.
asked Sep 23, 2011 in Trigonometry Answers by anonymous

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2 Answers

theta = x

(cos x) (sin 2x)-2 sin x + 2 = 0

(cos x) (sin 2x) - 2 sin x = -2

(cos x ) (2 (sin x) (cos x) ) - 2 sin x = -2

(2 sin x )( cos^2 (x) - 1) = -2

(2 sin x) (-sin^2(x)) = -2

-2 sin^3 (x) = -2

sin^3 (x) = 1

x = pi/2

Answer was confirmed with Mathematica.
answered Sep 23, 2011 by anonymous
its pie, because the butler did it... no one every suspects him :3
answered Aug 23, 2012 by anonymous
Your dumb

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