1812
Define 2 sequence formulas as follows...
X(1) = 2, X(n+1) = 3 X(n) + 1
and
Y(n) = 3 X(n)
Then it follows that X(1) = 2, Y(1) = 6
X(2) = 3 X(1) + 1 = 7, Y(2) = 3 x 7 = 21
X(3) = 3 X(2) + 1 = 22, Y(3) = 3 * 22 = 66
X(4) = 3 X(3) + 1 = 67, Y(4) = 3* 67 = 201
X(5) = 3 X(4) + 1 = 604, Y(5) = 3 * 604 = 1812