rektangel: 43 bi 53...want angels
angel at base from invers tangent 43/53= inv tan(0.811320754)
=39.053 deg (approx)
yu hav trianges with base=53 & 2 sides from the diagonals
base angels =39.05+39.05=78.11 deg
so big angel=180-78.11 =101.893726 deg weer 2 diagonals meet
smaller angel at meet point=78.11