2y+x-2z=6

x+3y-3z=10
x+4y+6z=24
asked Nov 21, 2012 in least common multiple by anonymous

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1 Answer

2y+x-2z=6  ------------- (1)

x+3y-3z=10 ------------ (2)

x+4y+6z=24   --------- (3)

From (2), x = 10 - 3y + 3z. Substitute for x into (1) and (3).

-y+z = -4  --------- (4)

y+9z = 14  ------- (5)

From (4), y = z + 4. Substitute into (5) for y.

z + 4 + 9z = 14

10z = 10

z = 1,      Therefore,

y = 5

z = -2

Answer: x = -2, y = 5, z = 1

answered Nov 1, 2015 by Fermat Level 10 User (62,800 points)
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