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All but one of the interior angles of a convex polygon measure 163. How many sides could the polygon have?

Please help me understand this. Thanks.

Please help me understand this. Thanks.

All of the interiour angles must add up to 180 degrees, so 3. The side can't be more than 180 by definition, and polygons are measured in 180s.

This statement is not true. They add up to multiples of 180...

which of these shapes is a four sided figure with only one pair of parellel sides?

1) trapezoid

2) rectangle

3) square

4) rhombus

1) trapezoid

2) rectangle

3) square

4) rhombus

This is a new question. You can ask it from http://mathhomeworkanswers.org/ask to get more help.

The formula to find the interior angles a polygon is (n-2)180 = measure of an angle.

(n-2) 180 = 163

n-2 = 180/163

n-2 = .905

n = 3

The answer is three!

[(n-2)x180]/n=interior angle measure of any regular polygon

Above is the formula for finding the number of sides to a regular polygon. Because what you describe is not a regular polygon, an** irregular**, it is** impossible **to decipher what the amount of sides, therefore you have given everybody a **trick question** to answer. This leaves all answers before this null and void with inaccurate result. Also waltjhall has the wrong formula and obviously does not realize that you can never have a decimal in the number that n is equal to.

Dear math haomework answers i need to know how many sides does a polygon have if you get this mesage please answer

John Bartlett johnboybartlett@yahoo.com

then senter angel=360/n...n=number sides

outside angel=senter angel, so inside angel=180-outside=180-senter angel

angel=180 -(360/n) & yu want it tu be 163 deg

180-163=17=360/n

so n=360/17=21.176

regular polygon with 21 sides hav senter angel=17.142857 & inside angel=263.86725

or tri 20 sides: inside=180-18=162 deg

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