f(x) = 6x^3-7x^2+1
f(x) = 6x^3-7x^2+0x+1
the first term is x+1 or x-1
______________
x-1)6x^3-7x^2+0x+1
1 | 6 -7 0 1
|____6_-1-1___
6 -1 -1 0
So the first term is (x-1) and 6x^2-x-1
Using rainbow method
6x^2-x-1, a=6, b = -1, c=-1
Rewrite drop a and multiply c by a
x^2 – x – 6 factor
(x - 3)(x + 2)now divide the numbers by 6
(x-3/6)(x +2/6)
(x – ½)(x+1/3) since they are not whole numbers move the denominators up
(2x - 1) (3x + 1)
The three terms are (x-1) (2x-1) (3x+1) set to 0
x =1, x=1/2, x=-1/3