x + 3 = 0
x = - 3
3 is the valuable solution.
Can i solve the original equation to find the extraneous solution?
(x - 9)(x + 3) = 0(x - 9) [Multiply by )x - 9) on each side.]
x = 9, - 3
9 is the extraneous solutionIn this way, i can get number of extraneous solutions..is it true?