⅓πr²h=768π, so r²h=2304=2⁸×3², so there are a number of possible integer answers:
r |
r² |
h |
1 |
1 |
2304 |
2 |
4 |
576 |
3 |
9 |
256 |
4 |
16 |
144 |
6 |
36 |
64 |
8 |
64 |
36 |
12 |
144 |
16 |
16 |
256 |
9 |
24 |
576 |
4 |
48 |
2304 |
1 |
The most sensible solutions are ones where r and h have values of similar order, such as 12 and 16.