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The length of a rectangle is 2 inches less than twice its width. the area of the rectangles is 40 square inches find the length and width.

Lenght (L)

Width (W)

Area (A) = 40 sq in

L = 2W - 2 ← call this eq1

A = L x W ← call this eq2

substitute eq1 to eq2

A = (2W - 2) x W

40 = 2W² - 2W

2W² - 2W - 40 = 0

divide by 2

W² - W - 20 = 0

W = [-(-1) ±√1 - 4(-20)]/2(1)

w = 1 ±√81

W = 1±9/2

W = [1 + 9 ] / 2

**W = 5**

Substitute W = 5 to eq1

L = 2W - 2

L = 2(5) - 2

L = 10 - 2

**L = 8**

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