The length of a rectangle is 2 inches less than twice its width. the area of the rectangles is 40 square inches find the length and width.
asked Oct 27, 2011 in Word Problem Answers by anonymous
edited Nov 5, 2011 by mshelton

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3 Answers

The length of a rectangle is 2 inches less than twice its width. the area of the rectangles is 40 square inches find the length and width.

Lenght (L)

Width (W)

Area (A) = 40 sq in

L = 2W - 2 ← call this eq1

A = L x W ← call this eq2

substitute eq1 to eq2

A = (2W - 2) x W

40 = 2W² - 2W

2W² - 2W - 40 = 0

divide by 2

W² - W - 20 = 0

W = [-(-1)  ±√1 - 4(-20)]/2(1)

w = 1 ±√81

W = 1±9/2

W = [1 + 9 ] / 2

W = 5

Substitute W = 5 to eq1

L = 2W - 2

L = 2(5) - 2

L = 10 - 2

L = 8

 

answered Nov 7, 2011 by E♥Lim Level 3 User (2,700 points)
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