(1) 4x-3
(2) -10x⁻³-9x⁻²=-(10/x³+9/x²)=-(10+9x)/x³
(3) Assuming f(x)=5x^¾-⅖x³, df/dx=(15/4)x^-¼-6x²/5
(4) f(x)=6x²-19x+15, df/dx=12x-19
(5) ((x-3)-x)/(x-3)²=-3/(x-3)²
(6) f(x)=x³/(1-x²),
df/dx=(3(1-x²)x²+2x⁴)/(1-x²)²=
(3x²-3x⁴+2x⁴)/(1-x²)²=
(3-x²)x²/(1-x²)²
(7) 2x√2+2=2(x√2+1)
(8) (4x+x⁻⁵)^-⅔(4-5x⁻⁶)/3