First, we make all the numbers the same length by prefixing zeroes. The longest number has 8 digits, so we use leading zeroes for numbers with fewer than 8 digits.
0 8 7 6 5 4 3 1
0 6 5 6 6 6 8 7
0 0 8 7 6 5 4 3
7 6 5 4 3 4 3 3
0 0 0 8 7 6 5 5
A gap has been left before each digit to leave space for a marker.
Starting on the bottom left we add together the digits in the same column and we insert a marker when this sum exceeds 10, and we keep in mind the residue. We're essentially adding digits a pair at a time. The first column presents no problem so we simply write down 7 (temporarily) as the sum of the first column, but the second column illustrates the method better. Starting at the bottom, we have the digits 0 6 0 6 8. The zeroes we can ignore. So 6+6=12. We place a marker in front of the second 6 and keep in mind the residue 2. We add 2 to 8=10 and we insert another marker to the left of 8 and record the sum as 0. So far we have:
0•8 7 6 5 4 3 1
0•6 5 6 6 6 8 7
0 0 8 7 6 5 4 3
7 6 5 4 3 4 3 3
0 0 0 8 7 6 5 5
7 0
next column: 0 5 8 5 7 we proceed the same. Ignore the zero; 5+8=13; mark the 8 and keep 3 in mind. Add 3 to 5=8, then add 7 to 8=15, and insert another marker before 7. Put 5 in the answer.
0•8•7 6 5 4 3 1
0•6 5 6 6 6 8 7
0 0•8 7 6 5 4 3
7 6 5 4 3 4 3 3
0 0 0 8 7 6 5 5
7 0 5
We continue this way up to the last column:
0•8•7•6 5 4 3 1
0•6 5•6•6•6•8 7
0 0•8 7 6 5•4•3
7 6 5•4•3•4 3 3
0 0 0 8 7 6 5 5
7 0 5 1 7 5 3 9
+2 2 3 2 2 2 1 (sum of markers)
9 2 8 3 9 7 4 9
Now we count the markers. Between the first and second columns we have 2 markers so we add 2 to the result of the first column to give us 9 replacing the 7. Then 0+2=2, 5+3=8, and so on. We do this up to the last column. I've shown the sum of the markers for each column. The Vedic arithmetic only requires you to be able to add only the numbers 1 to 9 together. The faster you can do this the faster you can do Vedic addition (drop tens method).