Write the factors of 14 in pairs: (1,14), (2,7) and write the difference of these factors: 13,5. We want a difference of 5 for the middle coefficient, 5, the second pair (2,7). Treat (2x+3y) as a single unit (as if there were only one variable X=2x+3y), then factorisation is:
(2x+3y+2)(2x+3y-7)