Do you mean 3.15x2-5089x=2.63?
If so, x2-5089x/3.15=2.63/3.15.
But 2.63/3.15 is very small compared to 5089/3.15 so let's ignore it (treat it as zero) to get an approximate solution:
x2-5089x/3.15=0, x(x-5089/3.15)=0 so x≈0 or x≈5089/3.15=7×727/(7×0.45)=727/0.45=14540/9.
14540/9=16155/9.