Assuming that a and b are the legs of a right triangle such that tanθ=a/b; and c is the hypotenuse, such that a²+b²=c², then tanθ=6/9=⅔, c=√(36+81)=√97.
So we have:
sinθ=a/c=6/√97=6√97/97 in standard form;
cosθ=b/c=9/√97=9√97/97,
tanθ=⅔,
cotθ=3/2 or 1½,
cscθ=√97/6,
secθ=√97/9.
√97=9.8484 approx.
sinθ=0.6092, cosθ=0.9138, tanθ=0.6667,
cscθ=1.6415, secθ=1.0943, cotθ=1.5.