log[2(x2+5x-2)]=log[2(x2+3x-6)]+log(49)=log[98(x2+3x-6)],
2(x2+5x-2)=98(x2+3x-6),
x2+5x-2=49(x2+3x-6)=49x2+147x-294,
48x2+142x-292=0,
24x2+71x-146=0,
x=(-71±√(5041+4×24×146))/48=(-71±√19057)/48=1.3968 or -4.3551 approx.
When x=1.3968, x2+5x-2>0 and x2+3x-6>0 so this solution is valid because the logs can be computed.
When x=-4.3551, x2+5x-2<0 and x2+3x-6<0 so this solution is invalid because the logs cannot be computed.
SOLUTION x=1.3968 approx.