a=27, b=13.8, C=53
me assume a=length av base, b=length av 1 side up from base,
& C=angel tween thees 2 sides
thus, base=27 & 1 side is 53 deg up from base & this side is 13.8
hite=13.8*tan(53 deg)=13.8*1.327044822=18.31321854
area=(1/2)*hite*base=18.313*27/2=247.22845
the "vertex"...=top av triangel...we hav the y part, need tu get x
x=13.8*kosine(53 deg)=13.8*0.601815023=8.30504732