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People say that it depends on what "valid" variable you us, or that you have to assume this or that in the "missing" pattern, but you really don't.

The simple formula for this is x^2+x=y or if you want, x*x+x=y.

You don't even have to calculate the "missing" numbers.

9*9+9 = 81+9 = 90. So y=90.

The answer is:90

6 x 1 = 6 +6 = 12 (the next answer)

12 x 1 = 12 + 8 = 20 (the next answer)

20 x 1 = 20 + 10 = 30 (the next answer)

30 x 1 = 30 + 12 = 42 (the next answer)

42 x 1 = 42 + 14 = 56!!!!

2x3 = 6

3x4= 12

4x5 = 20

5x6 = 30

6x7 = 42

7x8 = 56

8x9 = 72

9x10 = 90

3 = 12 3x4 =12

4 = 20 4x5 = 20

5 = 30 5x6 = 30

6 = 42 6x7 = 42

7 = 49 7x8 = 56

8 = 64 8x9=72

9 = 90 9x10 = 90

pattern is 2x current number added to the previous answer

so

last number is 6 = 42 so

9 = (9x2) or 18 + 42

9 = 60

#include <stdio.h>

int main (int argc, const char * argv[]) {

int n=0; int x=0;

while( n++ < 20 )

{

x = n * ( n + 1 );

printf("%i : %i \n", n, x);

}

return 0;

6+3*2=12

12+4*2=20

20+5*2=30

30+6*2=42 then

42+9*2=**60**

Therefore 9 = 60

if 2 = 6, 3 =12, 4 = 20, 5 = 30, 6 = 42 then 9 = ?

2=6(4)

3=12(6)

4=20(8)

5=30(10)

6=42(12)

7=56(14)

8=72(16)

9=90(18)

10=110(20)

9=90

if 2 = 6, 3 =12, 4 = 20, 5 = 30, 6 = 42 then 9 = ?

2=6(4)

3=12(6)

4=20(8)

5=30(10)

6=42(12)

7=56(14)

8=72(16)

9=90(18)

Para ser 90, a matriz precisava deixar claro que existe o 7 e 8.

Isto não ocorre. Acredito que o resultado mais provável seja **58**, pois o resultado é sempre a soma dos números da esquerda , diagonal acima e superior + 1:

12 =( 6 + 3 + 2) + 1

20 =(12 + 4 + 3) + 1

30 = (20 + 5 + 4) + 1

42 = (30 + 6 + 5) + 1

?? = (42 + 6 + 9) + 1 = **58**

I think is: Number X Next position Number from the given variables.

2 = 6 , so 2x3=6

3 = 12, 3x4=12

4 = 20, 4x5 = 20

5 = 30, 5x6 = 30

6 = 42, 6x7 = 42

9 = 9x10 = 90

once you guys realize that this isn't really a math problem & that the whole equation is incorrect..Then you'll understand why...the answer is..... 9

3 = 12 (+ 6)

4 = 20 (+ 8)

5 = 30 (+ 10)

6 = 42 (+12)

7 = 66 (+14)

8 = 82 (+ 16)

9 = 100 (+ 18)

Each successive number is arrived at by adding a progressively larger number (larger by 2) to the result.

...