y - 5 = log(x) --- (1)
y = 6 - log(x - 3) --- (2)
Substituting (2) into (1), we have:
6 - log(x - 3) - 5 = log(x)
6 - 5 - log(x - 3) = log(x)
1 = log(x - 3) + log(x)
1 = log(x(x - 3))
1 = log(x^2 - 3x)
10^1 = x^2 - 3x
x^2 - 3x - 10 = 0
(x - 5)(x + 2) = 0
x = 5 or x = -2 (rejected, since log (-2) does not exist)
Substituting x = 5 into (2), we have:
y = 6 - log(5 - 3)
y = 6 - log(2)
Hence, we have x = 5 and y = 6 - log(2)