root(x)+y=11 root(y)+x=7
or,{root(x)-2}+y-9=0 or,{root(y)-3}+x-4=0
So,{root(x)-2}+y-9={root(y)-3}+x-4=0
Now,x-root(x)-2=y-root(y)-6=0 (cause they are factorable , either not possible)
so,factoring, x-root(x)-2 ={root(x)-2}{root(x)+1}=0 , Or, root(x)=2 as root(x)=-1 is absurd here
again,factoring, y-root(y)-6={root(y)-3}{root(y)+2}=0 , Or, root(y)=3 as root(y)=-2 is again absurd here
Thus,root(x)=2 Or,x=4 And root(y)=3 Or,y=9 [New Method Crack By Safal Das Biswas Savm Chinsurah]