Math Homework Answers - Recent questions and answers
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Powered by Question2AnswerAnswered: 2.Which is a correct classification of DEF with vertices D(-3,-2). E(-2,3) and F(1,0)?
http://www.mathhomeworkanswers.org/127379/which-is-correct-classification-of-def-with-vertices-3-and-0?show=238931#a238931
2. Scalene triangle<br />
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3. Insufficient info; but guess AD=BC, so 5y+7=7y-3; 10=2y, y=5<br />
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4. c<br />
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5. cOther Math Topicshttp://www.mathhomeworkanswers.org/127379/which-is-correct-classification-of-def-with-vertices-3-and-0?show=238931#a238931Sun, 26 Feb 2017 15:46:27 +0000Answered: Solve f(x)=|x-2|
http://www.mathhomeworkanswers.org/127263/solve-f-x-x-2?show=238929#a238929
<p>f(2)=0, f(3)=f(1)=1. Graph:</p>
<p><img alt="" src="http://www.mathhomeworkanswers.org/?qa=blob&qa_blobid=16152305074096531185" style="height:157px; width:300px"></p>Algebra 1 Answershttp://www.mathhomeworkanswers.org/127263/solve-f-x-x-2?show=238929#a238929Sun, 26 Feb 2017 13:03:37 +0000Answered: express in standard firm x(x-m)=2x-m
http://www.mathhomeworkanswers.org/127307/express-in-standard-firm-x-x-m-2x-m?show=238928#a238928
Expand brackets: x^2-mx=2x-m. x^2-mx-2x+m=0.<br />
<br />
Standard form x^2-(m+2)x+m=0.Other Math Topicshttp://www.mathhomeworkanswers.org/127307/express-in-standard-firm-x-x-m-2x-m?show=238928#a238928Sun, 26 Feb 2017 12:54:46 +0000Answered: solving word problems with matrix
http://www.mathhomeworkanswers.org/127505/solving-word-problems-with-matrix?show=238927#a238927
<p>4+5+6=15 so the amounts invested are 4/15*1200=$320 (x), <strong>5/15*1200=$400 (y) and $480 (z).</strong></p>
<p><strong>Amount invested in z is $480.</strong></p>
<p>x+y+z=700, so z+140+z=700, 2z=560, <strong>z=$280, cash inflow for z.</strong></p>
<p><strong>x+y+280=700, x+y=$420 or x+y=280+140=$420, combined inflow for x and y.</strong></p>
<p><strong>Amount invested in y is $400.</strong></p>Word Problem Answershttp://www.mathhomeworkanswers.org/127505/solving-word-problems-with-matrix?show=238927#a238927Sun, 26 Feb 2017 12:52:01 +0000Answered: geometry proof
http://www.mathhomeworkanswers.org/127562/geometry-proof?show=238926#a238926
<p><img alt="" src="http://www.mathhomeworkanswers.org/?qa=blob&qa_blobid=12176512439869882289" style="height:159px; width:350px"></p>
<p style="text-align:justify">ABCD is a parallelogram.</p>
<p style="text-align:justify">In triangles ABD and BCD, BD, the diagonal of ABCD, is common to both triangles.</p>
<p style="text-align:justify">Angles BDA and DBC are equal (alternate angles between parallel lines)</p>
<p style="text-align:justify">Angles ABD and BDC are equal for the same reason.</p>
<p style="text-align:justify">The triangles are congruent (ASA) therefore BC=AD and AB=DC, the opposite sides of ABCD are equal (congruent).</p>Geometry Answershttp://www.mathhomeworkanswers.org/127562/geometry-proof?show=238926#a238926Sun, 26 Feb 2017 12:40:01 +0000Answered: Find the first derivative of y = √(x-3)
http://www.mathhomeworkanswers.org/238919/find-the-first-derivative-of-y-%E2%88%9A-x-3?show=238925#a238925
y'=½(x-3)^-½=1/(2√(x-3))Calculus Answershttp://www.mathhomeworkanswers.org/238919/find-the-first-derivative-of-y-%E2%88%9A-x-3?show=238925#a238925Sun, 26 Feb 2017 09:24:52 +0000Answered: Solve for x, 2[x+2/2x-3]-9[2x-3/x+2]=3, x is not equal to -2 and 3/2
http://www.mathhomeworkanswers.org/238910/solve-for-x-2-x-2-2x-3-9-2x-3-x-2-3-x-is-not-equal-to-2-and-3-2?show=238917#a238917
<p><a rel="nofollow" href="http://mathhomeworkanswers.org/238910/solve-for-x-2-x-2-2x-3-9-2x-3-x-2-3-x-is-not-equal-to-2-and-3-2">Solve for x, 2[x+2/2x-3]-9[2x-3/x+2]=3, x is not equal to -2 and 3/2 </a></p>
<p>I assume the equation should be,</p>
<p>2[(x + 2)/(2x - 3)] - 9[(2x-3)/(x + 2)] = 3 multiply both sides by (2x - 3)(x + 2)</p>
<p>2(x + 2)^2 - 9(2x-3)^2 = 3(2x - 3)(x + 2) expanding the brackets</p>
<p>2x^2 + 8x + 8 - 36x^2 + 108x - 81 = 6x^2 + 3x - 18</p>
<p>40x^2 - 113x + 55 = 0</p>
<p>(8x - 5)(5x - 11) = 0</p>
<p><span style="text-decoration: underline;"><strong>Answer: x = 5/8, x = 11/5</strong></span></p>Other Math Topicshttp://www.mathhomeworkanswers.org/238910/solve-for-x-2-x-2-2x-3-9-2x-3-x-2-3-x-is-not-equal-to-2-and-3-2?show=238917#a238917Sat, 25 Feb 2017 21:30:09 +0000Answered: Find the slope of the line through the points P and Q when P=(1,5) , Q=(2,7)
http://www.mathhomeworkanswers.org/238909/find-the-slope-of-the-line-through-the-points-p-and-q-when-5-q-2-7?show=238916#a238916
<p><a rel="nofollow" href="http://mathhomeworkanswers.org/238909/find-the-slope-of-the-line-through-the-points-p-and-q-when-5-q-2-7">Find the slope of the line through the points P and Q when P=(1,5) , Q=(2,7) </a></p>
<p>The (x,y) coordinates for the points P and Q are,</p>
<p>P = (1,5) and Q = (2,7)</p>
<p>The slope between these two points, m, is the ratio of the difference between the y-values to the difference between the x-values.</p>
<p>i.e. m = (y1 - y2) / (x1 - x2)</p>
<p>m = (5 - 7) / (1 - 2)</p>
<p>m = (-2) /(-1) = 2 / 1</p>
<p><span style="text-decoration: underline;"><strong>Answer: slope, m = 2 </strong></span></p>
<p>It doesn't mattter which y-value you take first in the numerator, as long as you take the x-value for the same point first in the denominator.</p>Calculus Answershttp://www.mathhomeworkanswers.org/238909/find-the-slope-of-the-line-through-the-points-p-and-q-when-5-q-2-7?show=238916#a238916Sat, 25 Feb 2017 21:01:01 +0000Answered: If x is to 9 as 8 is to 12, then x is equal to
http://www.mathhomeworkanswers.org/196104/if-x-is-to-9-as-8-is-to-12-then-x-is-equal-to?show=238911#a238911
<p><span style="font-family:georgia,serif"><span style="color:#FF0000">the answer is six</span></span></p>
<p><span style="font-family:georgia,serif"><span style="color:#FF0000">your welcome for the help im very sure of this answer</span></span></p>Other Math Topicshttp://www.mathhomeworkanswers.org/196104/if-x-is-to-9-as-8-is-to-12-then-x-is-equal-to?show=238911#a238911Sat, 25 Feb 2017 18:05:27 +0000Answered: Given f(x)=1-3x² determine f'x from first principles,determine the equation of the tangent of f at x=-2
http://www.mathhomeworkanswers.org/238902/given-determine-first-principles-determine-equation-tangent?show=238908#a238908
<p style="text-align:justify">f'(x)=-6x and f'(-2)=12 the gradient or tangent slope.</p>
<p style="text-align:justify">If y=mx+c is the general equation of the tangent, m=gradient=12.</p>
<p style="text-align:justify">f(-2)=1-3*4=-11, so the tangent is at (-2,-11) which must lie on the tangent line, so:</p>
<p style="text-align:justify">-11=12(-2)+c, -11=-24+c, and c=13, so y=g(x)=12x+13 is the equation of the tangent.</p>
<p style="text-align:justify">DERIVATION OF DIFFERENTIAL</p>
<p style="text-align:justify">f(x+h)=1-3(x+h)^2=1-3x^2-6xh-3h^2.</p>
<p style="text-align:justify">∂f=f(x+h)-f(x)=-6xh-3h^2; ∂f/h=-6x-3h where ∂f is the change in f when x goes from x to x+h. h becomes ∂x, infinitesimally small, and can be ignored in comparison to x, so ∂f/∂x=f'(x)=-6x.</p>Calculus Answershttp://www.mathhomeworkanswers.org/238902/given-determine-first-principles-determine-equation-tangent?show=238908#a238908Sat, 25 Feb 2017 15:28:42 +0000Answered: If the Branding division were to experience the same percentage increase from Year 2 to Year 3 as they did from Year 1 to Year 2, what would the Branding division’s revenue be in Year 3 (rounded)
http://www.mathhomeworkanswers.org/238901/branding-division-experience-percentage-increase-divisions?show=238907#a238907
<p style="text-align: justify;">5000000/1000000=5 is the growth factor between Year 1 and Year 2. Percentage increase is 400%.</p>
<p style="text-align: justify;">So Year 3 must be 5 times Year 2=5*5000000= 25 million=5000000+4*5000000.</p>Word Problem Answershttp://www.mathhomeworkanswers.org/238901/branding-division-experience-percentage-increase-divisions?show=238907#a238907Sat, 25 Feb 2017 15:21:04 +0000Answered: -4x+7(3x+15)=20
http://www.mathhomeworkanswers.org/238900/4x-7-3x-15-20?show=238906#a238906
Expand brackets:<br />
<br />
-4x+21x+105=20<br />
<br />
17x+105=20<br />
<br />
subtract 105 from each side:<br />
<br />
17x=-85<br />
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Divide through by 17:<br />
<br />
x=-5Algebra 1 Answershttp://www.mathhomeworkanswers.org/238900/4x-7-3x-15-20?show=238906#a238906Sat, 25 Feb 2017 15:15:25 +0000Answered: express62dividedby3to3decialplaces
http://www.mathhomeworkanswers.org/238892/express62dividedby3to3decialplaces?show=238905#a238905
<p style="text-align:justify">62/3=60/3+2/3=20+2/3. As a decimal 2/3 is 0.6666... recurring. A recurring decimal equivalent fraction is of the form xxx/999 where xxx is recurring, so the number corresponding to xxx can be written as X. Therefore X/999=2/3 and X=2/3*999=666. but we know that a recurring decimal just goes on forever so 0.6666... rounds up to 0.667 in 3 decimal places. the answer is 20.667.</p>Algebra 1 Answershttp://www.mathhomeworkanswers.org/238892/express62dividedby3to3decialplaces?show=238905#a238905Sat, 25 Feb 2017 15:06:10 +0000Answered: Name three 2-digit numbers that divide into 1520 with a remainder of 8. Explain how you found your answers.
http://www.mathhomeworkanswers.org/238890/three-digit-numbers-divide-remainder-explain-found-answers?show=238904#a238904
<p style="text-align:justify">First subtract 8 from 1520 to give 1512. The required numbers will divide exactly into 1512.</p>
<p style="text-align:justify">Now we need 2-digit factors of 1512=2^3*3^3*7. we can make 21, 24, 56, 63, 72 out of these.</p>
<p style="text-align:justify">These include the quoted answers.</p>Word Problem Answershttp://www.mathhomeworkanswers.org/238890/three-digit-numbers-divide-remainder-explain-found-answers?show=238904#a238904Sat, 25 Feb 2017 14:59:35 +0000Answered: find the value of sin[tan^-1 (1/2) without using a calculatore. draw the reference triangle
http://www.mathhomeworkanswers.org/22259/find-value-without-using-calculatore-draw-reference-triangle?show=238856#a238856
<p><img alt="" src="http://www.mathhomeworkanswers.org/?qa=blob&qa_blobid=16288205849435367129" style="height:214px; width:350px"></p>
<p style="text-align: justify;">The picture shows the reference triangle. The hypotenuse has length √(2^2+1^2)=√5 by Pythagoras. The tangent of the left angle is 1/2 so its sine is 1/√5 or √5/5.</p>
<p> </p>
<p> </p>Trigonometry Answershttp://www.mathhomeworkanswers.org/22259/find-value-without-using-calculatore-draw-reference-triangle?show=238856#a238856Fri, 24 Feb 2017 13:00:16 +0000Answered: How to draw 125, 100, 80, 70degree angles without using compass?
http://www.mathhomeworkanswers.org/37508/how-to-draw-125-100-80-70degree-angles-without-using-compass?show=238855#a238855
<p><img alt="" src="http://www.mathhomeworkanswers.org/?qa=blob&qa_blobid=12209012609095319752" style="height:248px; width:400px"></p>
<p style="text-align:justify">The picture illustrates how to form the required angles. Graph paper is best to use, along with a straight edge or ruler. A protractor is not needed. The angles at P, Q and R are right angles, and you can make these using a set square if you are not using graph paper. The line measurements can be any units as long as the horizontal and vertical measurements use the same unit.</p>
<p style="text-align:justify">Some of the angles are marked. If you position the points A, B and D accurately you will find the following angles:</p>
<p style="text-align:justify">AOQ=125; the angle of 100 is shown on BO produced and AOB=AOQ-BOP=125-45=80; DOQ=AOR=55, and AOD=AOQ-DOQ=125-55=70. So the angles you need are AOQ=125 (shown), AOB=80 and supplementary angle 100 (shown) on BO produced, AOD=70. (AOQ is an approximation with 0.01% error.)</p>Geometry Answershttp://www.mathhomeworkanswers.org/37508/how-to-draw-125-100-80-70degree-angles-without-using-compass?show=238855#a238855Fri, 24 Feb 2017 12:43:35 +0000Answered: How to make a 125 degree angle without compass
http://www.mathhomeworkanswers.org/238853/how-to-make-a-125-degree-angle-without-compass?show=238854#a238854
<p>Use graph paper as shown:</p>
<p><img alt="" src="http://www.mathhomeworkanswers.org/?qa=blob&qa_blobid=9161651350196885881" style="height:267px; width:350px"></p>
<p style="text-align:justify">This construction uses graph paper, but no protractor or compasses are needed, just a straight edge or ruler. The angle is very close to 125 degrees (99.99% accurate), and is probably as accurate as you're going to get by hand. Instead of graph paper you can use a set square and ruler to give you the right angle and measurements.</p>Geometry Answershttp://www.mathhomeworkanswers.org/238853/how-to-make-a-125-degree-angle-without-compass?show=238854#a238854Fri, 24 Feb 2017 11:38:21 +0000Answered: How many parallelograms are in an octagonal prism?
http://www.mathhomeworkanswers.org/49490/how-many-parallelograms-are-in-an-octagonal-prism?show=238819#a238819
it is 8 parallelogramsGeometry Answershttp://www.mathhomeworkanswers.org/49490/how-many-parallelograms-are-in-an-octagonal-prism?show=238819#a238819Thu, 23 Feb 2017 22:46:30 +0000Answered: adx/(b-c)yz=bdy/(c-a)zx=cdz/(a-b)xy
http://www.mathhomeworkanswers.org/238815/adx-b-c-yz-bdy-c-a-zx-cdz-a-b-xy?show=238816#a238816
<p style="text-align:justify">(1) I am assuming this is not a calculus question where dx, dy and dz have a different meaning.</p>
<p style="text-align:justify"><span style="background-color:rgba(255, 255, 255, 0)">Variable d can be removed as a common factor:</span></p>
<p style="text-align:justify"><span style="background-color:rgba(255, 255, 255, 0)">ax/((b-c)yz)=by/((c-a)zx)=cz/((a-b)xy)</span></p>
<p style="text-align:justify"><span style="background-color:rgba(255, 255, 255, 0)">Take the first pair and remove common factor z:</span></p>
<p style="text-align:justify"><span style="background-color:rgba(255, 255, 255, 0)">ax/((b-c)y)=by/((c-a)x); ax^2(c-a)=by^2(b-c); ax^2=by^2(b-c)/(c-a); by^2=ax^2(c-a)/(b-c)</span></p>
<p style="text-align:justify"><span style="background-color:rgba(255, 255, 255, 0)">The second pair have common factor x:</span></p>
<p style="text-align:justify"><span style="background-color:rgba(255, 255, 255, 0)">by^2(a-b)=cz^2(c-a); by^2=cz^2(c-a)/(a-b); cz^2=by^2(a-b)/(c-a)</span></p>
<p style="text-align:justify"><span style="background-color:rgba(255, 255, 255, 0)">First and last have common factor y:</span></p>
<p style="text-align:justify"><span style="background-color:rgba(255, 255, 255, 0)">ax^2(a-b)=cz^2(b-c); ax^2=cz^2(b-c)/(a-b); cz^2=ax^2(a-b)/(b-c)</span></p>
<p style="text-align:justify"><span style="background-color:rgba(255, 255, 255, 0)">We have a pair of equations for each of the three quantities ax^2, by^2, cz^2.</span></p>
<p><span style="background-color:rgba(255, 255, 255, 0)">So,</span></p>
<p>ax^2=by^2(b-c)/(c-a)=cz^2(b-c)/(a-b), by^2/(c-a)=cz^2/(a-b) or</p>
<p>(A) by^2/(cz^2)=(c-a)/(a-b)</p>
<p>by^2=ax^2(c-a)/(b-c)=cz^2(c-a)/(a-b), ax^2/(b-c)=cz^2/(a-b) or</p>
<p>(B) ax^2/(cz^2)=(b-c)/(a-b)</p>
<p>cz^2=by^2(a-b)/(c-a)=ax^2(a-b)/(b-c), by^2/(c-a)=ax^2/(b-c) or</p>
<p>(C) by^2/(ax^2)=(c-a)/(b-c)</p>
<p>The relative sizes of a, b and c can be:</p>
<p>(1) a<b<c (2) a<c<b (3) b<a<c (4) b<c<a (5) c<a<b (6) c<b<a</p>
<p style="text-align:justify">The quotient of two squares is always positive, so we can see the relative signs of the quotients of the other variables.</p>
<p style="text-align:justify">Apply each of these to (A), (B) and (C), looking for consistency:</p>
<p style="text-align:justify">(1A)<0 implies bc<0 and b<0, c>0 because b<c (1B)>0 implies ac>0 and a>0 because c>0 (1C)<0 implies ab<0 and b<0 so b<a, but b>a: INCONSISTENT</p>
<p style="text-align:justify">(2A)<0 implies bc<0 and b>0, c<0 because b>c (2B)<0 implies ac<0 and a>0 because c<0 (2C)>0 implies ab>0 and b>0 but c<0 and a>0 making c<a, but c>a: INCONSISTENT</p>
<p style="text-align:justify">(3A)>0 implies bc>0 (3B)<0 implies ac<0 and a<0, c>0 and b>0 because a<c (3C)<0 implies ab<0 and b>0 and so b>a, but b<a: INCONSISTENT</p>
<p style="text-align:justify">(4A)<0 implies bc<0 and b<0, c>0 because b<c (4B)<0 implies ac<0 and a<0 because c>0 (4C)>0 implies ab>0, true, because a and b are both negative, but c<a making c<0 when c>0: INCONSISTENT</p>
<p style="text-align:justify">(5A)>0 implies bc>0 (5B)<0 implies ac<0 and c<0, b<0, a>0 because a>c (5C)<0 implies ab<0, but b>a which cannot be if b<0: INCONSISTENT</p>
<p style="text-align:justify">(6A)<0 implies bc<0 and c<0, b>0 because b>c (6B)>0 implies ac>0 and a<0, but b<a and b>0 which cannot be: INCONSISTENT</p>
<p style="text-align:justify">So there are no solutions because there is inconsistency throughout.</p>
<p style="text-align:justify">(2) I am assuming this is a calculus problem.</p>
<p>Assume a, b and c are constants and x, y and z are variables.</p>
<p>adx/((b-c)y)=bdy/((c-a)x); b(b-c)ydy=a(c-a)xdx</p>
<p style="text-align:justify">Integrating: b(b-c)y^2/2=a(c-a)x^2/2 (constant to be added later)</p>
<p>a(c-a)x^2-b(b-c)y^2=k a constant.</p>
<p style="text-align:justify">A similar result follows for the other two pairs of variables (x,z and y,z) by separation of variables and using the other two pairs of equations:</p>
<p style="text-align:justify">a(a-b)x^2-c(b-c)z^2=p and b(a-b)y^2-c(c-a)z^2=q</p>
<p style="text-align:justify"> </p>Other Math Topicshttp://www.mathhomeworkanswers.org/238815/adx-b-c-yz-bdy-c-a-zx-cdz-a-b-xy?show=238816#a238816Thu, 23 Feb 2017 20:06:26 +0000Answered: X to the power of 8 subtract y to the power of 8
http://www.mathhomeworkanswers.org/238809/x-to-the-power-of-8-subtract-y-to-the-power-of-8?show=238813#a238813
<p style="text-align: justify;">x^8-y^8=(x^4-y^4)(x^4+y^4)=(x^2-y^2)(x^2+y^2)(x^4+y^4)=(x-y)(x+y)(x^2+y^2)(x^4+y^4).</p>
<p style="text-align: justify;">The solution can be taken further, but it involves complex expressions.</p>
<p style="text-align: justify;">For example, x^2+y^2=(x+iy)(x-iy), x^4+y^4=(x^2+iy^2)(x^2-iy^2).</p>Algebra 2 Answershttp://www.mathhomeworkanswers.org/238809/x-to-the-power-of-8-subtract-y-to-the-power-of-8?show=238813#a238813Thu, 23 Feb 2017 17:54:43 +0000Answered: 5x-2x^3+8x^2-7 in standard form.
http://www.mathhomeworkanswers.org/238777/5x-2x-3-8x-2-7-in-standard-form?show=238811#a238811
-2x^3+8x^2+5x-7Algebra 1 Answershttp://www.mathhomeworkanswers.org/238777/5x-2x-3-8x-2-7-in-standard-form?show=238811#a238811Thu, 23 Feb 2017 17:46:52 +0000Answered: How many ways can you choose 1 red ball?
http://www.mathhomeworkanswers.org/7865/how-many-ways-can-you-choose-1-red-ball?show=238740#a238740
<p style="text-align:justify">Imagine the balls are of two colours but of different sizes. This makes each red ball and white ball unique.</p>
<p style="text-align:justify">The possible colour outcomes are RRR, RRW, RWR, RWW, WRR, WRW, WWR, WWW.</p>
<p style="text-align:justify">But when we consider each ball as unique we get different numbers. For example, RRR could be R1R2R3, R1R2R4, R1R2R5, etc. The number of permutations is 9*8*7=504. The number of combinations is 504/6=84, because the number of ways of arranging 3 balls is 6. The permutation R1R2R3 is not the same as R2R3R1, for example. But the combination R1R2R3 is the same as the combination R2R3R1.</p>
<p style="text-align:justify">(1) The balls are picked at random and returned after selection.</p>
<p style="text-align:justify">Now consider probabilities. P(R) is the probability of picking a red ball, so P(R)=9/15=3/5 and 1-P(R)=P(W)=2/5. There are 3 ways of picking exactly one red: RWW, WRW, WWR and so P(RWW)=P(WRW)=P(WWR)=(3/5)(2/5)^2=12/125. Add the three together and we get 36/125. That means that if the number of outcomes is N, then the number of ways of picking just one red is 36N/125. So we need to define and find N. Considering the uniqueness of each ball there are 15^3=3375 outcomes. So N=3375 and 36/125 of 3375=972. There are 972 ways of selecting exactly one red ball (any one of 9 reds) out of a possible 3375 outcomes.</p>
<p style="text-align:justify">(2) The three balls are selected at the same time without returning any.</p>
<p style="text-align:justify">This alters the probability and the number of outcomes. N=2730 (=15*14*13). The probabilities also change. Let's look at RWW, WRW, WWR. P(RWW)=9/15*6/14*5/13; P(WRW)=6/15*9/14*5/13; P(WWR)=6/15*5/14*9/13. Note that these all have the same value=9/91, so when added together we have 27/91. When we apply this to N=2730, we get 27*2730/91=810 ways.</p>Statistics Answershttp://www.mathhomeworkanswers.org/7865/how-many-ways-can-you-choose-1-red-ball?show=238740#a238740Thu, 23 Feb 2017 12:41:50 +0000Answered: two fair dice one red one green, how many ways can you roll a 5
http://www.mathhomeworkanswers.org/59870/two-fair-dice-one-red-one-green-how-many-ways-can-you-roll-a-5?show=238739#a238739
<p style="text-align: justify;">The possible combinations are 1+4, 2+3, 3+2, 4+1, making 4 ways in all. (That's a probability of 4/36=1/9.)</p>Algebra 1 Answershttp://www.mathhomeworkanswers.org/59870/two-fair-dice-one-red-one-green-how-many-ways-can-you-roll-a-5?show=238739#a238739Thu, 23 Feb 2017 12:02:30 +0000Answered: Two fair six-sided dice are colored red and green, Determine the probability that the number rolled on the red die divided by the number rolled on the green die is a whole number.
http://www.mathhomeworkanswers.org/238720/colored-determine-probability-number-divided-number-number?show=238736#a238736
<p style="text-align: justify;">First, we need to find out which combinations lead to the required result. A table helps.</p>
<table border="1" cellpadding="1" cellspacing="1" style="width:500px">
<tbody>
<tr>
<td> </td>
<td>G1</td>
<td>G2</td>
<td>G3</td>
<td>G4</td>
<td>G5</td>
<td>G6</td>
</tr>
<tr>
<td>R1</td>
<td>1</td>
<td> </td>
<td> </td>
<td> </td>
<td> </td>
<td> </td>
</tr>
<tr>
<td>R2</td>
<td>2</td>
<td>1</td>
<td> </td>
<td> </td>
<td> </td>
<td> </td>
</tr>
<tr>
<td>R3</td>
<td>3</td>
<td> </td>
<td>1</td>
<td> </td>
<td> </td>
<td> </td>
</tr>
<tr>
<td>R4</td>
<td>4</td>
<td>2</td>
<td> </td>
<td>1</td>
<td> </td>
<td> </td>
</tr>
<tr>
<td>R5</td>
<td>5</td>
<td> </td>
<td> </td>
<td> </td>
<td>1</td>
<td> </td>
</tr>
<tr>
<td>R6</td>
<td>6</td>
<td>3</td>
<td>2</td>
<td> </td>
<td> </td>
<td>1</td>
</tr>
</tbody>
</table>
<p style="text-align:justify">The filled cells are the only whole number quotients and there are 14 of them, so the probability is 14/36=7/18.</p>Word Problem Answershttp://www.mathhomeworkanswers.org/238720/colored-determine-probability-number-divided-number-number?show=238736#a238736Thu, 23 Feb 2017 08:37:21 +0000Answered: how to find the height of a trapezoid with only bases and sides
http://www.mathhomeworkanswers.org/238730/how-to-find-the-height-of-trapezoid-with-only-bases-and-sides?show=238735#a238735
<p>In any trapezoid, if the sides are equal, then the trapezoid is symetrical, as shown below.</p>
<p><img alt="" src="http://www.mathhomeworkanswers.org/?qa=blob&qa_blobid=7136858989081293882" style="height:334px; width:600px"></p>
<p>By a simple application of Pythagoras' theorem, we can show that</p>
<p><span style="text-decoration: underline;"><strong>Trapezoid height = 8 </strong></span></p>Geometry Answershttp://www.mathhomeworkanswers.org/238730/how-to-find-the-height-of-trapezoid-with-only-bases-and-sides?show=238735#a238735Thu, 23 Feb 2017 07:58:10 +0000Answered: one-half the total of six times a number n and twenty-six
http://www.mathhomeworkanswers.org/238729/one-half-the-total-of-six-times-a-number-n-and-twenty-six?show=238734#a238734
<p><a rel="nofollow" href="http://mathhomeworkanswers.org/238729/one-half-the-total-of-six-times-a-number-n-and-twenty-six">one-half the total of six times a number n and twenty-six </a></p>
<p>Let n be the number.</p>
<p>Then total, T = 6n + 26</p>
<p>So, half total = T/2 = 3n + 13</p>
<p><span style="text-decoration: underline;"><strong>Answer: 3n + 13</strong></span></p>Algebra 1 Answershttp://www.mathhomeworkanswers.org/238729/one-half-the-total-of-six-times-a-number-n-and-twenty-six?show=238734#a238734Thu, 23 Feb 2017 07:22:17 +0000Answered: A science museum has a scale model of a ladybug. In the model, 50 centimeters represents 9 millimeters. The length of the model is 1 meter. How long is the actual ladybug?
http://www.mathhomeworkanswers.org/238728/science-ladybug-centimeters-represents-millimeters-ladybug?show=238733#a238733
<p><a rel="nofollow" href="http://mathhomeworkanswers.org/238728/science-ladybug-centimeters-represents-millimeters-ladybug">A science museum has a scale model of a ladybug. In the model, 50 centimeters represents 9 millimeters. The length of the model is 1 meter. How long is the actual ladybug?</a></p>
<p>50 cm represents 9 mm, so</p>
<p>100 cm = 18 mm, but</p>
<p>100 cm = 1 m, which is the lemgth of the model. So</p>
<p><span style="text-decoration: underline;"><strong>Actual lenght of bug is 18 mm</strong></span></p>Word Problem Answershttp://www.mathhomeworkanswers.org/238728/science-ladybug-centimeters-represents-millimeters-ladybug?show=238733#a238733Thu, 23 Feb 2017 07:19:25 +0000Answered: after 5% reduction, you purchase a new stereo for $384.75. What was the price of the stereo before the reduction?
http://www.mathhomeworkanswers.org/238723/after-reduction-purchase-stereo-price-stereo-before-reduction?show=238732#a238732
<p>after 5% reduction, you purchase a new stereo for $384.75. What was the price of the stereo before the reduction?</p>
<p>If $384.75 is the price after a 5% reduction, then $384.75 represents 95% of the original price.</p>
<p>i.e. original price = 384.75/0.95 = 405.00</p>
<p><span style="text-decoration: underline;"><strong>Price before reduction is $405.00</strong></span></p>Word Problem Answershttp://www.mathhomeworkanswers.org/238723/after-reduction-purchase-stereo-price-stereo-before-reduction?show=238732#a238732Thu, 23 Feb 2017 07:14:01 +0000Answered: Make x the subject: y/x^2 = (1-1/x^2)/(x^2 - x)
http://www.mathhomeworkanswers.org/238679/make-x-the-subject-y-x-2-1-1-x-2-x-2-x?show=238731#a238731
<p><a href="http://mathhomeworkanswers.org/238679/make-x-the-subject-y-x-2-1-1-x-2-x-2-x" rel="nofollow">Make x the subject: y/x^2 = (1-1/x^2)/(x^2 - x) </a></p>
<p>y/x^2 = (1-1/x^2)/(x^2 - x) (multiply both sides by x^2)</p>
<p>y = (x^2 - 1)/(x^2 - x) (now factorise both top and bottom of rhs)</p>
<p>y = [(x - 1)(x + 1)] / [x(x - 1)] cancel the common factor, (x - 1)</p>
<p>y = (x + 1)/x</p>
<p>y = 1 + 1/x</p>
<p>1/x = y - 1</p>
<p><span style="text-decoration: underline;"><strong>x = 1/(y - 1)</strong></span></p>Other Math Topicshttp://www.mathhomeworkanswers.org/238679/make-x-the-subject-y-x-2-1-1-x-2-x-2-x?show=238731#a238731Thu, 23 Feb 2017 07:05:31 +0000Answered: 4x squared divided by two??
http://www.mathhomeworkanswers.org/23750/4x-squared-divided-by-two?show=238727#a238727
Answer is 99Algebra 1 Answershttp://www.mathhomeworkanswers.org/23750/4x-squared-divided-by-two?show=238727#a238727Thu, 23 Feb 2017 01:28:07 +0000Answered: what order from least to greatest do u put these fractions in:3/4 2/3 5/8
http://www.mathhomeworkanswers.org/15974/what-order-from-least-to-greatest-do-put-these-fractions-in-5?show=238678#a238678
What is the order of 0.49, 0.82, 2 from least to greatestAlgebra 1 Answershttp://www.mathhomeworkanswers.org/15974/what-order-from-least-to-greatest-do-put-these-fractions-in-5?show=238678#a238678Wed, 22 Feb 2017 21:24:25 +0000Answered: 57436+23521 using method 1
http://www.mathhomeworkanswers.org/238637/57436-23521-using-method-1?show=238675#a238675
<p style="text-align:justify">Whatever method is used the answer will be the same:</p>
<p style="text-align:justify"> </p>
<p style="text-align:justify"> </p>
<p style="text-align:justify">57436 +</p>
<p style="text-align:justify"><span style="text-decoration: underline;">23521</span></p>
<p style="text-align:justify">70957 +</p>
<p style="text-align:justify"><span style="text-decoration: underline;">10000</span></p>
<p style="text-align:justify"><span style="text-decoration: underline;">80957</span> because 7+3=10 so there is a carryover to the next column on the left.</p>Other Math Topicshttp://www.mathhomeworkanswers.org/238637/57436-23521-using-method-1?show=238675#a238675Wed, 22 Feb 2017 21:11:38 +0000Answered: 100951765:82872581::6571564:?
http://www.mathhomeworkanswers.org/238571/100951765-82872581-6571564?show=238664#a238664
<p style="text-align: justify;">If the question means 100951765/82872581=6571564/? Then the answer is:</p>
<p style="text-align: justify;">6571564*82872581/100951765=5394680 approx.</p>Other Math Topicshttp://www.mathhomeworkanswers.org/238571/100951765-82872581-6571564?show=238664#a238664Wed, 22 Feb 2017 20:38:25 +0000Answered: Differentiation of terminal velocity final equation
http://www.mathhomeworkanswers.org/238499/differentiation-of-terminal-velocity-final-equation?show=238647#a238647
<p style="text-align:justify">When the drag force and force due to gravity are equal the terminal velocity is reached. Various factors are involved: 0.5dv^2AC=mg where d=air density, v=terminal velocity, A=surface area presented to the air, C=drag coefficient, assumed constant. The air density changes gradually with altitude, being densest near the ground. Although g does change with altitude, the change is very small compared to other factors so it can be regarded as constant at about 9.8m/s^2. A is constant as long as the falling object is not rotating. The mass, m, of the object is constant for a coherent object. From this v=√(2mg/dAC).</p>
<p style="text-align:justify">DERIVATION USING CALCULUS</p>
<p style="text-align:justify">We have to start by assuming the drag force at some velocity v is 0.5dv^2AC.</p>
<p style="text-align:justify">So if x is the altitude where x=0 is ground level, then gravity acts in the negative direction and drag in the positive direction. F=ma is Newton's Law and we can replace F with 0.5dv^2AC-mg, the net result of drag and gravitation. Initial velocity at time t=0 is zero so the only force is gravity -mg. As the object accelerates under gravity v increases. The acceleration a can be written dv/dt or v'.</p>
<p style="text-align:justify">So we have mv'=0.5dv^2AC-mg or v'=0.5dv^2AC/m-g=g(0.5dv^2AC/mg-1). Note that v is the vertical velocity upwards.</p>
<p style="text-align:justify">We can write this in the form of integrands, but before we do, let's simplify this a bit. We know which of these are constants so we can combine them into just one called k, where k^2=0.5dAC/mg. v'=g(k^2v^2-1).</p>
<p style="text-align:justify">∫(dv/(k^2v^2-1))=g∫dt. </p>
<p style="text-align:justify">Integrating by parts we have:</p>
<p style="text-align:justify">∫(dv/(2(kv-1)))-∫(dv/(2(kv+1)))=gt. (We'll insert the constant of integration later.)</p>
<p style="text-align:justify">ln(kv-1)/2k-ln(kv+1)/2k=gt; ln((kv-1)/(kv+1))=2kgt+C, where C is the constant of integration.</p>
<p style="text-align:justify">However, when v=0, t=0 so that would give us ln(-1)=C which has no meaning. So let's rephrase the original integrand: ∫(dv/(1-k^2v^2))=-g∫dt.</p>
<p style="text-align:justify">Now we have ∫(dv/(2(1-kv))+∫(dv/(2(1+kv))=-gt and</p>
<p style="text-align:justify">-ln(1-kv)+ln(1+kv)=-2kgt+C. This time when v=t=0, C=0, so ln((1+kv)/(1-kv))=-2kgt.</p>
<p style="text-align:justify">So (1+kv)/(1-kv)=e^(-2kgt).</p>
<p style="text-align:justify">After some time t=T the object reaches terminal velocity, but by definition the velocity stays constant and the object keeps falling at the same constant rate. If we imagine the object falls from a very great height so as never to reach the ground, t can be made infinite for all intents and purposes, and the right-hand side approaches zero. Therefore 1+kv=0 and v=-1/k=-√(2mg/dAC). The negative sign simply means the velocity is in the downward direction. A truer interpretation is that the falling object never reaches a terminal velocity no matter how far it falls, so the terminal velocity is in fact an asymptote.</p>
<p style="text-align:justify">v=-(1/k)(1-e^(-2kgt))/(1+e^(-2kgt)) is the actual equation for v.</p>
<p style="text-align:justify">For practical purposes, though, given sufficient altitude, over the range for which the quantities assumed to be constant are approximately constant, the terminal velocity has meaning.</p>
<p style="text-align:justify"> </p>
<p style="text-align:justify"> </p>Calculus Answershttp://www.mathhomeworkanswers.org/238499/differentiation-of-terminal-velocity-final-equation?show=238647#a238647Wed, 22 Feb 2017 17:03:28 +0000Answered: [ 12:02:19 PM ] Guest : If I get paid 0.01875 cents per lb, how much money will I get for 588245lbs?
http://www.mathhomeworkanswers.org/238585/guest-paid-01875-cents-per-how-much-money-will-for-588245lbs?show=238602#a238602
<p style="text-align:justify">0,01875c pays for 1 lb so 0.01875*588245 pays for 588245lb=11029.59375 cents or about $110.30.</p>Word Problem Answershttp://www.mathhomeworkanswers.org/238585/guest-paid-01875-cents-per-how-much-money-will-for-588245lbs?show=238602#a238602Wed, 22 Feb 2017 12:58:55 +0000Answered: one+one=two
http://www.mathhomeworkanswers.org/32403/one-one-two?show=238589#a238589
964d8ceFactors of a numberhttp://www.mathhomeworkanswers.org/32403/one-one-two?show=238589#a238589Tue, 21 Feb 2017 23:06:46 +0000Answered: What is the height of a lamp whose radii are 20cm and 30cm and slant height is 40cm respectively
http://www.mathhomeworkanswers.org/238493/what-height-whose-radii-20cm-slant-height-40cm-respectively?show=238584#a238584
<p>The lamp appears to be a truncated cone.</p>
<p><img alt="" src="http://www.mathhomeworkanswers.org/?qa=blob&qa_blobid=6871210289673334005" style="height:461px; width:250px"></p>
<p style="text-align:justify">To find the dimensions of the full cone we use similar right triangles, half the width of the lamp. The slant height of the top part of the cone we call x so the slant height of the whole cone is x+40, and we have x/(x+40)=20/30=2/3 because the cross-section of the cones form similar triangles. Therefore, cross-multiplying we have 3x=2(x+40)=2x+80, and from this x=80. The total slant height of the large cone is 80+40=120.</p>
<p style="text-align:justify">The vertical height of the full cone is √(120^2-30^2) (Pythagoras)=30√15 and the height of the smaller cone is √(80^2-20^2)=20√15 (or 2/3*30√15) so the height of the lamp is the difference=10√15=38.73cm approx.</p>
<p style="text-align:justify"> </p>Other Math Topicshttp://www.mathhomeworkanswers.org/238493/what-height-whose-radii-20cm-slant-height-40cm-respectively?show=238584#a238584Tue, 21 Feb 2017 17:00:22 +0000Answered: 4(x+1)^2-9(y+1)^2
http://www.mathhomeworkanswers.org/238474/4-x-1-2-9-y-1-2?show=238498#a238498
Difference of two squares:<br />
<br />
(2(x+1))^2-(3(y+1))^2=(2(x+1)-3(y+1))(2(x+1)+3(y+1))=<br />
<br />
(2x+2-3y-3)(2x+2+3y+3)=(2x-3y-1)(2x+3y+5)Algebra 2 Answershttp://www.mathhomeworkanswers.org/238474/4-x-1-2-9-y-1-2?show=238498#a238498Tue, 21 Feb 2017 08:08:00 +0000Answered: find the number of subgroups of a group G
http://www.mathhomeworkanswers.org/126206/find-the-number-of-subgroups-of-a-group-g?show=238497#a238497
We can apply Sylow's theorem part 2 to the problem, i.e. number if subgroups is of the form 7k+1=m where m divides 168 and m not equal to 1 by virtue of the nature of group being simple. Thus, the answer is 8Other Math Topicshttp://www.mathhomeworkanswers.org/126206/find-the-number-of-subgroups-of-a-group-g?show=238497#a238497Tue, 21 Feb 2017 07:51:07 +0000number of subgroups of odd order in the free product of a group
http://www.mathhomeworkanswers.org/238496/number-of-subgroups-of-odd-order-in-the-free-product-of-group
What is number of subgroups of odd index in the free product of a group with itself? Is there any algorithm for finding out?Other Math Topicshttp://www.mathhomeworkanswers.org/238496/number-of-subgroups-of-odd-order-in-the-free-product-of-groupTue, 21 Feb 2017 07:46:36 +0000Answered: Find the slope of a line segment points (10, 11) and (-10, -11)
http://www.mathhomeworkanswers.org/238452/find-the-slope-of-a-line-segment-points-10-11-and-10-11?show=238471#a238471
Slope=(11-(-11))/(10-(-10))=22/20=11/10. (Diff of y-coord)÷(Diff of x-coord).)Calculus Answershttp://www.mathhomeworkanswers.org/238452/find-the-slope-of-a-line-segment-points-10-11-and-10-11?show=238471#a238471Mon, 20 Feb 2017 17:38:16 +0000Answered: Find the equation of the lines that are both passing through the point (-5, 6) with slopes 2/3 and -4
http://www.mathhomeworkanswers.org/238451/find-equation-lines-that-passing-through-point-with-slopes?show=238470#a238470
<p style="text-align: justify;">The two lines have the form y=2x/3+a and y=-4x+b where we have to find a and b by plugging in (-5,6).</p>
<p style="text-align: justify;">6=-10/3+a, so a=28/3 and 3y=2x+28; and 6=20+b, b=-14 and y=-4x-14.</p>Calculus Answershttp://www.mathhomeworkanswers.org/238451/find-equation-lines-that-passing-through-point-with-slopes?show=238470#a238470Mon, 20 Feb 2017 17:36:19 +0000Answered: Find the equation of the line which contains the point (7, -1) and is parallel to the line 6x-2y=11
http://www.mathhomeworkanswers.org/238454/find-the-equation-line-which-contains-point-parallel-the-line?show=238469#a238469
<p style="text-align: justify;">Parallel lines have the same gradient which means that we can use the same coefficients and just change the constant: 6x-2y=a. To find a, plug in (7,-1): 42+2=44=a. So the equation is 6x-2y=44, which is the same as 3x-y=22 or y=3x-22.</p>Calculus Answershttp://www.mathhomeworkanswers.org/238454/find-the-equation-line-which-contains-point-parallel-the-line?show=238469#a238469Mon, 20 Feb 2017 17:31:24 +0000Answered: What are the coordinates of a circle with standard equation x^2+y^2=49? What is the value of the radius ?
http://www.mathhomeworkanswers.org/238450/coordinates-circle-with-standard-equation-what-value-radius?show=238468#a238468
<p style="text-align: justify;">x^2+y^2=49 is the equation of a circle centre at the origin (0,0) and radius=√49=7.</p>Calculus Answershttp://www.mathhomeworkanswers.org/238450/coordinates-circle-with-standard-equation-what-value-radius?show=238468#a238468Mon, 20 Feb 2017 17:26:15 +0000Answered: The Rectangle Problem
http://www.mathhomeworkanswers.org/238339/the-rectangle-problem?show=238439#a238439
<p>There is some difficulty interpreting this question.</p>
<p style="text-align:justify">The best interpretation I can offer is that, if the perimeter of two triangles is 144cm, what is the maximum difference in area between the two triangles, if the dimensions of the triangles are whole numbers?</p>
<p style="text-align:justify">The maximum area of a triangle is when the triangle is equilateral so its area is a/2 * a√3/2=a^2√3/4, where a is the side length, which is 144/3=48cm. The area is 576√3=997.66 sq cm approx.</p>
<p style="text-align:justify">The cosine formula can be used to relate the lengths of the sides:</p>
<p style="text-align:justify">a^2=b^2+c^2-2bccosA. If all the sides are integers, angle A must have a rational cosine. The only angles to do so are 0, 60, 90, 180 degrees. 0 and 180 would not make a triangle, so we are left with 60 and 90.</p>
<p style="text-align:justify">If A=60 we have a^2=b^2+c^2-bc and a+b+c=144cm. So (144-(b+c))^2=b^2+c^2-bc, from which we get:</p>
<p style="text-align:justify">144^2-288(b+c)+b^2+c^2+2bc=b^2+c^2-bc; and c=(6912-96b)/(96-b)=96(72-b)/(96-b).</p>
<p style="text-align:justify">When 96-b is a factor of 96 we will get an integer result for c: so b=64, 48 are obvious solutions, giving us c=24, 48. That gives us a=56, 48. When b=60, c=96*12/36=32 and a=52.</p>
<p style="text-align:justify">If A=90, 144^2-288(b+c)+2bc=0, c=144(72-b)/(144-b), and we get (a,b,c)=(65,63,16) and (60,48,36).</p>
<p style="text-align:justify">So now we have all the possible triangles: (56,64,24), (48,48,48), (52,60,32), (65,63,16) and (60,48,36). We identified the equilateral triangle area, so we are left with 4. The one with the shortest side is right triangle (65,63,16) and this one has the smallest area: 8*63 (half base of 16 times height of 63)=504 sq cm. the difference between the greatest and smallest area is 576√3-504=72(8√3-7)=493.66 sq cm.</p>
<p style="text-align:justify">FURTHER INTERPRETATION</p>
<p style="text-align:justify">After presenting this possible solution, I pondered over the use of the word "rectangle". Perhaps it was a loose translation of "right angle" implying that the only triangles to be considered were right triangles. In my solution, two such triangles were identified: (60,48,36) and (65,63,16), with areas respectively 864 sq cm and 504 sq cm. the greater area is (60,48,36). The areas of the associated rectangles (the triangles are formed by splitting the rectangles into two using the diagonals) are 1728 sq cm and 1008 sq cm, so the difference in the areas of the two triangles is 360 sq cm.</p>Word Problem Answershttp://www.mathhomeworkanswers.org/238339/the-rectangle-problem?show=238439#a238439Mon, 20 Feb 2017 13:59:24 +0000Answered: P=m+n+k for m
http://www.mathhomeworkanswers.org/238436/p-m-n-k-for-m?show=238438#a238438
P=m+n+k; subtract n+k from each side: P-n-k=m, so m=P-n-k.Algebra 2 Answershttp://www.mathhomeworkanswers.org/238436/p-m-n-k-for-m?show=238438#a238438Mon, 20 Feb 2017 11:29:09 +0000Answered: half o the question asks for the values of x and y if x+y=8
http://www.mathhomeworkanswers.org/238432/half-o-the-question-asks-for-the-values-of-x-and-y-if-x-y-8?show=238435#a238435
<p style="text-align:justify">The first part has the solutions x/y=-2 or -3. So x=-2y or -3y.
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Substitute for x in x+y=8: -2y+y=8, -y=8 so y=-8 and x=16; or
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-3y+y=8, -2y=8, y=-4 and x=12.
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Therefore the solutions are (16,-8) and (12,-4).</p>
<p style="text-align:justify">If you plug these into the original quadratic you will find that this pair of solutions makes the quadratic = 0.</p>Algebra 2 Answershttp://www.mathhomeworkanswers.org/238432/half-o-the-question-asks-for-the-values-of-x-and-y-if-x-y-8?show=238435#a238435Sun, 19 Feb 2017 23:37:13 +0000Answered: The ages a man and his two sons, Eric and John is in the ratio 12:4:3 If the difference between the ages of Eric and john is 5, find the ages of each of them
http://www.mathhomeworkanswers.org/238433/ages-eric-john-ratio-difference-between-ages-ages-each-them?show=238434#a238434
<p style="text-align:justify">Let the ages be F (father), E (Eric) and J (John).
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E-J=5. Also, F/E=12/4=3 and F/J=12/3=4.
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So E=F/3 and J=F/4, E-J=5 so F/3-F/4=5 or F(1/3-1/4)=5, F/12=5 and F=60.
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Therefore E=20 and J=15.
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The ages are: father=60, Eric=20 and John=15.</p>Word Problem Answershttp://www.mathhomeworkanswers.org/238433/ages-eric-john-ratio-difference-between-ages-ages-each-them?show=238434#a238434Sun, 19 Feb 2017 23:24:19 +0000Answered: what is 75% of 160
http://www.mathhomeworkanswers.org/17577/what-is-75%25-of-160?show=238431#a238431
<p><span style="background-color:transparent !important; color:rgb(0, 0, 0); font-family:arial">A wool<span style="font-family:arial,helvetica,sans-serif"></span> suit, discounted by </span></p>
<p><span style="background-color:transparent !important; color:rgb(0, 0, 0); font-family:arial">75%</span></p>
<p><span style="background-color:transparent !important; color:rgb(0, 0, 0); font-family:arial">for a clearance<span style="font-family:arial,helvetica,sans-serif"></span> sale, has a price tag of </span></p>
<p><span style="background-color:transparent !important; color:rgb(0, 0, 0); font-family:arial">$ 160</span></p>
<p><span style="background-color:transparent !important; color:rgb(0, 0, 0); font-family:arial">What was the<span style="font-family:arial,helvetica,sans-serif"></span> suit's original<span style="font-family:arial,helvetica,sans-serif"></span> price?</span></p>
<p> </p>Word Problem Answershttp://www.mathhomeworkanswers.org/17577/what-is-75%25-of-160?show=238431#a238431Sun, 19 Feb 2017 18:47:44 +0000Answered: how to find a base in a equation
http://www.mathhomeworkanswers.org/127269/how-to-find-a-base-in-a-equation?show=238345#a238345
<p style="text-align: justify;">If the initial population is P, then after no days y=P; after a day it's y=2P; two days y=4P. Therefore after x days it's y=(2^x)P so b=2.</p>Algebra 1 Answershttp://www.mathhomeworkanswers.org/127269/how-to-find-a-base-in-a-equation?show=238345#a238345Sun, 19 Feb 2017 02:42:58 +0000