Can you order the digits 1,2,3,4,5 and 6 to make a number which is divisible by 6 ... ... so that when the final or last digit is removed it becomes a 5-figure number divisible by 5? And when the final digit is removed again it becomes a 4-figure number divisible by 4? And when the final digit is removed again it becomes a 3-figure number divisible by 3? And when the final digit is removed again it becomes a 2-figure number divisible by 2, then finally a 1-figure number divisible by 1?