(3x-1+yx-3)/x-1y2=3/y2+yx-3/(x-1y2)=
3/y2+x-3+1/y=3/y2+x-2/y=3/y2+1/(x2y).
Another way to solve this is to multiply the numerator and denominator by x3:
(3x-1+yx-3)/x-1y2=(3x2+y)/(x2y2). If this is split into two fractions we get the same answer as above.