Given: f(x)=2lx-4l+6 First,draw a graph of f(x)=2lxl
1. On the interval x≥0: The graph is a ray that goes up rightwards at slope of 2:1.
2. On the interval x<0: The graph is the mirror of right-hand ray reflected about the y-axis. You now have a graph: f(x)=lxl. The slope of the left^hand ray is -2:1, The 2 rays opens upwards forming a letter-V vertex at the bottom: the origine of coordinate plane,O(0,0).
3. f(x)=2lx-4l is f(x)=lxl moved 4 units to the right. You dont need to draw the new graph, but just change the coordinates of vertex(0,0) to (4,0). You now have a new graph: f(x)=2lx-4l
4. f(x)=2lx-4l+6 is f(x)=2lx-4l moved 6 units upwards. Change the coordinates of vertex(4,0) to(4,6). Draw a new x-axis 4 units left fome the original, and a new y-axis 6 units downwards.
You now have the graph: f(x)=2lx-4l+6