please help me ty!!!
asked Jun 29, 2016 in Calculus Answers by Paul

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Assume this reads f(x)=6/(x^2+3).

The expression x^2+3 is minimum when x=0, so f(x) is maximum at x=0, f(0)=2.

Whether positive or negative, the square of x is positive so f(x)<2 for every value of x other than x=0. Therefore f(x) is concave downward (maximum) in the vicinity of x=0 and f(0) is the summit of a hill. The rest of the curve gets closer to the x axis as x increases positively or negatively.

answered Jun 29, 2016 by Rod Top Rated User (429,740 points)
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